Advertisements
Advertisements
Question
Advertisements
Solution
Case (i) Energy consumed by two bulbs per day
= 2 x `60 /1000` x 4= 0.48 kWh
Case (ii) Energy consumed by three bulbs per day
= 3 x `100/1000` x 5 = 1. 5 kWh
:. total energy consumed per day = 0.48 + 1.5 = 1.98 kWh
Required consumption of electrical during the month of June (30 days)=
= 1.98 x 30 = 59.4 kWh
APPEARS IN
RELATED QUESTIONS
At what frequency is AC supplied to residential houses?
Why is an electric light bulb not filled with air? Explain why argon or nitrogen is filled in an electric bulb.
What is the resistance, under normal working conditions of a 240 V electric lamp rated at 60 W? If two such lamps are connected in series across a 240 V mains supply, explain why each one appears less bright.
An electric iron rated 750 W is operated for 2 hours/day. How much energy is consumed by the electric iron for 30 days?
Why is heating element wound on a long porcelain rod in a room heater.
A cooler of 1500 W, 200 volts and a fan of 500 W, 200 volts are to be used from a household supply. The rating of fuse to be used is:
What is the commercial unit of electrical energy?
What is the commercial unit of electrical energy? Represent it in terms of joules.
Two heaters A and B have power rating of 1 kW and 2 kW, respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is ______
