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Question
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Solution
Case (i) Energy consumed by two bulbs per day
= 2 x `60 /1000` x 4= 0.48 kWh
Case (ii) Energy consumed by three bulbs per day
= 3 x `100/1000` x 5 = 1. 5 kWh
:. total energy consumed per day = 0.48 + 1.5 = 1.98 kWh
Required consumption of electrical during the month of June (30 days)=
= 1.98 x 30 = 59.4 kWh
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