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प्रश्न
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उत्तर
Case (i) Energy consumed by two bulbs per day
= 2 x `60 /1000` x 4= 0.48 kWh
Case (ii) Energy consumed by three bulbs per day
= 3 x `100/1000` x 5 = 1. 5 kWh
:. total energy consumed per day = 0.48 + 1.5 = 1.98 kWh
Required consumption of electrical during the month of June (30 days)=
= 1.98 x 30 = 59.4 kWh
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संबंधित प्रश्न
The unit for expressing electric power is:
(a) volt
(b) joule
(c) coulomb
(d) watt
Electrical power P is given by the expression P = (Q × V) ÷ time. What do the symbols Q and V represent?
Electrical power p is given by the expression P = (Q × V) ÷ time. Express the power P in terms of current and resistance explaining the meaning of symbols used there in.
An electric iron is rated at 750 W, 230 V. Calculate the electrical energy consumed by the iron in 16 hours .
A potential difference of 6 V is applied across a 3 Ω resistor. What is the current flowinq throuqh the circuit?
‘The current rating of a fuse is 5A’. Comment on this statement.
Find the energy released by a current of 0.25 amperes flowing through a heater for 5 minutes. The p.d. is 230 V.
The following table gives the electrical appliances used, their power and the average time for which they are used each day in a home. Estimate the monthly electricity bill if the rate is 60 paise per unit.
| Sr.no. | Name | Nos. | Power rating | Time/day |
| 1 | Bulb | 4 | 100 W | 7.5 hr |
| 2 | Fans | 2 | 50 W | 10 hr |
| 3 | T.V. | 1 | 100 W | 2 hr |
| 4 | Iron | 1 | 500 W | 1 hr |
| 5 | Electric stove | 1 | 750 W | 2 hr |
A conductor of 10 Ω is connected across a 6 V ideal source. The power supplied by the source to the conductor is ______.
