Advertisements
Advertisements
प्रश्न
Advertisements
उत्तर
Case (i) Energy consumed by two bulbs per day
= 2 x `60 /1000` x 4= 0.48 kWh
Case (ii) Energy consumed by three bulbs per day
= 3 x `100/1000` x 5 = 1. 5 kWh
:. total energy consumed per day = 0.48 + 1.5 = 1.98 kWh
Required consumption of electrical during the month of June (30 days)=
= 1.98 x 30 = 59.4 kWh
APPEARS IN
संबंधित प्रश्न
State two factors on which the electrical energy consumed by an electrical appliance depends.
Define watt-hour. How many joules are equal to 1 watt-hour?
Write an expression for the electrical power spent in flow of current through a conductor in terms of
(a) Resistance and potential difference, (b) current and resistance.
A current of 0.2 A flows through a wire whose ends are at a potential difference of 15 V.
calculate:
(i) the resistance of the wire and
(ii) the heat energy produced in 1 minute.
A geyser is rated 1500 W, 250 V. This geyer is connected to 250 V mains. Calculate:
(i) the current drawn
(ii) the energy consumed in 50 hours, and
(iii) the cost of energy consumed at Rs. 4.20 per kWh
A potential difference of 6 V is applied across a 3 Ω resistor. What is the current flowinq throuqh the circuit?
Why is a concave reflector placed behind the heating element in a room heater.
What is the resistance of an appliance rated at V volt, P watt?
Find the heat produced in joules when a current of 10 amperes flows through a connecting wire of resistance 2 × 10-2 ohms and heating element of resistance 250 ohms for 2 seconds.
