Question

In a house two 60 W electric bulbs are lighted for 4 hours, and three 100 W bulbs for 5 hours every day. How much is the electric energy consumed during the month of June?

Answer 1

Case (i) Energy consumed by two bulbs per day

= 2 x `60 /1000` x 4= 0.48 kWh

Case (ii) Energy consumed by three bulbs per day

= 3 x `100/1000` x 5 = 1. 5 kWh

:. total energy consumed per day = 0.48 + 1.5 = 1.98 kWh
Required consumption of electrical during the month of June (30 days)=
= 1.98 x 30 = 59.4 kWh