Advertisements
Advertisements
Question
In Fig. 14.46, the area of ΔABC (in square units) is
Options
15
10
7.5
2.5
Advertisements
Solution
The coordinates of A are (1, 3).
∴ Distance of A from the x-axis, AD = y-coordinate of A = 3 units
The number of units between B and C on the x-axis are 5.
∴ BC = 5 units
Now,
Area of ∆ABC = \[\frac{1}{2} \times BC \times AD = \frac{1}{2} \times 5 \times 3 = \frac{15}{2} = 7 . 5\] square units
Thus, the area of ∆ABC is 7.5 square units.
APPEARS IN
RELATED QUESTIONS
If (−2, 3), (4, −3) and (4, 5) are the mid-points of the sides of a triangle, find the coordinates of its centroid.
Find the point on x-axis which is equidistant from the points (−2, 5) and (2,−3).
In what ratio is the line segment joining the points (-2,-3) and (3, 7) divided by the y-axis? Also, find the coordinates of the point of division.
Prove that the points (4, 5) (7, 6), (6, 3) (3, 2) are the vertices of a parallelogram. Is it a rectangle.
Points A(-1, y) and B(5,7) lie on the circle with centre O(2, -3y).Find the value of y.
Find the value of a, so that the point ( 3,a ) lies on the line represented by 2x - 3y =5 .
The abscissa of any point on y-axis is
Find the value of a for which the area of the triangle formed by the points A(a, 2a), B(−2, 6) and C(3, 1) is 10 square units.
Write the ratio in which the line segment joining points (2, 3) and (3, −2) is divided by X axis.
what is the value of \[\frac{a^2}{bc} + \frac{b^2}{ca} + \frac{c^2}{ab}\] .
The distance between the points (cos θ, 0) and (sin θ − cos θ) is
The coordinates of the point on X-axis which are equidistant from the points (−3, 4) and (2, 5) are
If (−1, 2), (2, −1) and (3, 1) are any three vertices of a parallelogram, then
The ratio in which the x-axis divides the segment joining (3, 6) and (12, −3) is
If the points P (x, y) is equidistant from A (5, 1) and B (−1, 5), then
Point (3, 0) lies in the first quadrant.
The coordinates of two points are P(4, 5) and Q(–1, 6). Find the difference between their abscissas.
Co-ordinates of origin are ______.
