Advertisements
Advertisements
Question
In a cyclic quadrilateral ABCD if AB || CD and ∠B = 70°, find the remaining angles.
Advertisements
Solution
It is given that, ABCD is a cyclic quadrilateral such that AB || CD and `angle B = 70°`

Sum of pair of opposite angles of cyclic quadrilateral is 180°.
`angle B + angle D = 180°` (`angleB = 70° ` given)
So, `angle D = 110°`
Also AB || CD and BC transversal
So,
`angleB + angleC = 180°`
`angleC = 180 ° - 70° `
= 110°
Now
`angleA + angleC = 180°`
`angleA = 180 °- angleC `
= 180° - 110 °
= 70°
`angleD` = 180° - 70°
`angleD = 110°`
APPEARS IN
RELATED QUESTIONS
In Figure 1, common tangents AB and CD to the two circles with centres 01and 02 intersect at E. Prove that AB = CD.

Find the length of the tangent drawn from a point whose distance from the centre of a circle is 25 cm. Given that the radius of the circle is 7 cm.
In Fig., if AB = AC, prove that BE = EC

In fig.. O is the center of the circle and BCD is tangent to it at C. Prove that ∠BAC +
∠ACD = 90°
If O is the centre of a circle of radius r and AB is a chord of the circle at a distance r/2 from O, then ∠BAO =
In the given figure, chord EF || chord GH. Prove that, chord EG ≅ chord FH. Fill in the blanks and write the proof.

ABC is a triangle with AB = 10 cm, BC = 8 cm and AC = 6 cm (not drawn to scale). Three circles are drawn touching each other with the vertices as their centres. Find the radii of the three circles.

In the figure, O is the centre of the circle and ∠AOB = 90°, ∠ABC = 30°. Then find ∠CAB.

In the following figure, O is the centre of the circle. Shade the smaller segment of the circle formed by CP.

If radius of a circle is 5 cm, then find the length of longest chord of a circle.
