Advertisements
Advertisements
प्रश्न
In a cyclic quadrilateral ABCD if AB || CD and ∠B = 70°, find the remaining angles.
Advertisements
उत्तर
It is given that, ABCD is a cyclic quadrilateral such that AB || CD and `angle B = 70°`
Sum of pair of opposite angles of cyclic quadrilateral is 180°.
`angle B + angle D = 180°` (`angleB = 70° ` given)
So, `angle D = 110°`
Also AB || CD and BC transversal
So,
`angleB + angleC = 180°`
`angleC = 180 ° - 70° `
= 110°
Now
`angleA + angleC = 180°`
`angleA = 180 °- angleC `
= 180° - 110 °
= 70°
`angleD` = 180° - 70°
`angleD = 110°`
APPEARS IN
संबंधित प्रश्न
Fill in the blanks:
The centre of a circle lies in ____________ of the circle.
From an external point P, tangents PA and PB are drawn to the circle with centre O. If CD is the tangent to the circle at point E and PA = 14 cm. Find the perimeter of ABCD.
In fig. there are two concentric circles with Centre O of radii 5cm and 3cm. From an
external point P, tangents PA and PB are drawn to these circles if AP = 12cm, find the
tangent length of BP.
If the area of a circle is equal to sum of the areas of two circles of diameters 10 cm and 24 cm, then the diameter of the larger circle (in cm) is:
If all the sides of a parallelogram touch a circle, show that the parallelogram is a rhombus.
Draw a circle of radius 4.8 cm and mark its center as P.
(i) Draw radii PA and PB such that ∠APB = 45°.
(ii) Shade the major sector of the circle
Find the radius of the circle
Diameter = 30 cm
Circles with centres A, B and C touch each other externally. If AB = 3 cm, BC = 3 cm, CA = 4 cm, then find the radii of each circle.
Circles with centres A, B and C touch each other externally. If AB = 36, BC = 32, CA = 30, then find the radii of each circle.
The tangent at a point C of a circle and a diameter AB when extended intersect at P. If ∠PCA = 110°, find ∠CBA see figure
