Advertisements
Advertisements
प्रश्न
In a cyclic quadrilateral ABCD, if m ∠A = 3 (m ∠C). Find m ∠A.
Advertisements
उत्तर
It is given that
ABCD is cyclic quadrilateral and ` m angle A = 3 (m angle C ) `

We have to find `m angle A `
Since ABCD is cyclic quadrilateral and sum of opposite pair of cyclic quadrilateral is 180°.
So ` angle A + angle C = 180°`
And
`3angleC + angleC = 180°`
`4angleC = 180°`
`angleC = (180°)/4`
= 45°
Therefore
`angleA = 3 xx 45° `
= 135°
Hence `angle A = 135°`
APPEARS IN
संबंधित प्रश्न
Prove that the line segment joining the points of contact of two parallel tangents of a circle, passes through its centre.
In fig., O is the centre of the circle, PA and PB are tangent segments. Show that the quadrilateral AOBP is cyclic.
In the given figure, a triangle ABC is drawn to circumscribe a circle of radius 2 cm such that the segments BD and DC into which BC is divided by the point of contact D, are of lengths 4 cm and 3 cm respectively. If the area of ΔABC = 21 cm2 then find the lengths of sides AB and AC.

On a semi-circle with AB as diameter, a point C is taken, so that m (∠CAB) = 30°. Find m(∠ACB) and m (∠ABC).
A chord of length 14 cm is at a distance of 6 cm from the centre of a circle. The length of another chord at a distance of 2 cm from the centre of the circle is
Draw circle with diameter: 8.4 cm
In above case, measure the length of the radius of the circle drawn.
Find the diameter of the circle
Radius = 8 cm
Find the radius of the circle
Diameter = 30 cm
Let s denote the semi-perimeter of a triangle ABC in which BC = a, CA = b, AB = c. If a circle touches the sides BC, CA, AB at D, E, F, respectively, prove that BD = s – b.
Assertion (A): If the circumference of a circle is 176 cm, then its radius is 28 cm.
Reason (R): Circumference = 2π × radius of a circle.
