Advertisements
Advertisements
प्रश्न
AD is a diameter of a circle and AB is a chord If AD = 30 cm and AB = 24 cm then the distance of AB from the centre of the circle is
विकल्प
10 cm
9 cm
8 cm
6 cm
Advertisements
उत्तर
9 cm
Explanation;
Hint:
In ΔAOC,
AO = 15 cm
AC = `1/2` AB
= `1/2 xx 24`
= 12 cm
In ΔAOC,
OC2 = AO2 – AC2
= 152 – 122
= 225 – 144
= 81
OC = `sqrt(81)`
= 9 cm
APPEARS IN
संबंधित प्रश्न
If the quadrilateral sides touch the circle prove that sum of pair of opposite sides is equal to the sum of other pair.
true or false
The degree measure of an arc is the complement of the central angle containing the arc.
In the fig below, it is given that O is the centre of the circle and ∠AOC = 150°. Find
∠ABC.
The point of concurrence of all angle bisectors of a triangle is called the ______.
A, B, C are any points on the circle with centre O. If m(arc BC) = 110° and m(arc AB) = 125°, find measure arc AC.
In figure, chords AC and DE intersect at B. If ∠ABE = 108°, m(arc AE) = 95°, find m(arc DC).
In figure, tangents PQ and PR are drawn to a circle such that ∠RPQ = 30°. A chord RS is drawn parallel to the tangent PQ. Find the ∠RQS.
[Hint: Draw a line through Q and perpendicular to QP.]
In the following figure, ∠ADC = 130° and chord BC = chord BE. Find ∠CBE.
Find the length of the arc of a circle which subtends an angle of 60° at the centre of the circle of radius 42 cm.
In the given figure, O is the centre of the circle. If ∠AOB = 145°, then find the value of x.
