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Question
In a single throw of two dice, find the probability of getting a doublet of even numbers.
Sum
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Solution
Given: A single throw of two fair six-sided dice; find probability of a doublet of even numbers.
Step-wise calculation:
1. Total number of possible outcomes
= 6 × 6
= 36
2. Even faces on a die are {2, 4, 6}.
Doublets of even numbers both dice same even are (2, 2), (4, 4), (6, 6).
Number of favourable outcomes = 3.
3. Probability = `"Number of favourable outcomes"/"Total outcomes"`
= `3/36`
= `1/12`
The probability of getting a doublet of even numbers in one throw of two dice is `1/12`.
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Chapter 22: Probability - Exercise 22A [Page 505]
