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Question
In a single throw of two dice, find the probability of getting a total of 9 or 11.
Sum
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Solution
Given:Two fair six-sided dice are thrown once; find P(total = 9 or 11).
Step-wise calculation:
1. Total possible ordered outcomes
= 6 × 6
= 36
2. Outcomes giving total 9: (3, 6), (4, 5), (5, 4), (6, 3) → 4 outcomes.
3. Outcomes giving total 11: (5, 6), (6, 5) → 2 outcomes.
4. Total favourable outcomes
= 4 + 2
= 6
5. Probability = `"Favourable"/"Total"`
= `6/36`
= `1/6`
= 0.1667
The probability of getting a total of 9 or 11 in one throw of two dice is `1/6`.
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Chapter 22: Probability - Exercise 22A [Page 505]
