Question

In a single throw of two dice, find the probability of getting a sum greater than 9.

Answer 1

Given: Two fair six-sided dice are thrown once. Find P(sum > 9).

Step-wise calculation:

1. Total possible equally likely outcomes = 6 × 6 = 36.

2. Sums greater than 9 are 10, 11, 12.

List of favourable outcomes:

Sum 10: (4, 6), (5, 5), (6, 4) 3 outcomes

Sum 11: (5, 6), (6, 5) 2 outcomes

Sum 12: (6, 6) 1 outcome

Total favourable outcomes = 3 + 2 + 1 = 6.

3. Probability = `"Favourable"/"Total"`

= `6/36`

= `1/6`

The probability of getting a sum greater than 9 in a single throw of two dice is `1/6`.