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Question
In a photoelectric experiment, the stopping potential is 1.5V. What is the maximum kinetic energy of a photoelectron?
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Solution
Given:
Vs = 1.5 V
To find: Maximum kinetic energy = ?
We know that KEmax = eVs
= 1.6 × 10-19 × 1.5
∴ KE max = 2.4 × 10-19 J
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