English

If the total energy of radiation of frequency 1014 Hz is 6.63 J, Calculate the number of photons in the radiation.

Advertisements
Advertisements

Question

If the total energy of radiation of frequency 1014 Hz is 6.63 J, Calculate the number of photons in the radiation. 

Sum
Advertisements

Solution

Given:

E = 6.63 J, ν = 1014 Hz,
We know, h = 6.63 × 10–34 Js.

To find: Number of photons (n)   

Formula: n = `"E"/"hv"`

Calculation:

Using formula,

n = `6.63/(6.63 xx 10^-34 xx 10^14)`

∴ n = 1020 

The number of photons emitted in the radiation is 1020.  

shaalaa.com
  Is there an error in this question or solution?
Chapter 14: Dual Nature Of Radiation And Matter - Short Answer I

APPEARS IN

SCERT Maharashtra Physics [English] Standard 12 Maharashtra State Board
Chapter 14 Dual Nature Of Radiation And Matter
Short Answer I | Q 5

RELATED QUESTIONS

Is it always possible to see the photoelectric effect with a red light?


Observations from an experiment on the photoelectric effect for the stopping potential by varying the incident frequency were plotted. The slope of the linear curve was found to be approximately 4.1 × 10−15 V s. Given that Exercises the charge of an electron is 1.6 × 10−19 C, find the value of the Planck’s constant h.

Using the values of work function given in the following table, tell which metal will require the highest frequency of incident radiation to generate photocurrent.

Typical values of work function for some common metals

Metal Work function (in eV)
Potassium 2.3
Sodium 2.4
Calcium 2.9
Zinc 3.6
Silver 4.3
Aluminium 4.3
Tungsten 4.5
Copper 4.7
Nickel 5.0
Gold 5.1

It is observed in an experiment on the photoelectric effect that an increase in the intensity of the incident radiation does not change the maximum kinetic energy of the electrons. Where does the extra energy of the incident radiation go? Is it lost? State your answer with explanatory reasoning.


Photocurrent recorded in the microammeter in an experimental setup of the photoelectric effect vanishes when the retarding potential is more than 0.8 V if the wavelength of incident radiation is 4950 Å. If the source of incident radiation is changed, the stopping potential turns out to be 1.2 V. Find the work function of the cathode material and the wavelength of the second source.


Find the energy of photon which have momentum 2 × 10-16 gm-cm/sec.  


The work function of a surface is 3.1 eV. A photon of frequency 1 × 1015 Hz. Is an incident on it. Calculate the incident wavelength is photoelectric emission occurs or not.   


A metal surface is illuminated by light of given intensity and frequency to cause photoemission. If the intensity of illumination is reduced to one-fourth of its original value then the maximum KE of the emitted photoelectrons would be ______.


The work function of a metal is 1.6 x 10-19 J. When the metal surface is illuminated by the light of wavelength 6400 Å, then the maximum kinetic energy of emitted photo-electrons will be (Planck's constant h = 6.4 x 10-34 Js) ____________.


Light of wavelength `lambda` strikes a photo-sensitive surface and electrons are ejected with kinetic energy E. If the kinetic energy is to be increased to 2E, the wavelength must be changed to `lambda'` where ____________.


Light of frequency 2 times the threshold frequency is incident on a photo sensitive material. If the frequency is made `1/3`rd and intensity is doubled then the photocurrent will ______.


When wavelength of incident radiation on the metal surface is reduced from 'λ1' to 'λ2', the kinetic energy of emitted photoelectrons is tripled. The work function of the metal is ______.
(h = Planck's constant, c =velocity of light)


When light of wavelength 'λ' is incident on a photosensitive surface, the stopping potential is 'V'. When light of wavelength '3λ' is incident on the same surface, the stopping potential is `"V"/6`. Threshold wavelength for the surface is _______.


Light of different frequencies, whose photons have energies 3 eV and 18 eV respectively, successively illuminate a metal of work function 2 eV. The ratio of the maximum speeds of the emitted electrons will be ______.


The work function of a substance is 4.0 eV. The longest wavelength of light that can cause photo-emission from this substance is approximately (h = 6.63 × 10-34 Js)[1eV = 1.6 × 10-19 J]


Which one of the following statements ts INCORRECT for stopping potential in photoelectric emission?


A metal surface having work function 'w0' emits photoelectrons when photons of energy 'E' are incident on it. The electron enters the uniform magnetic field (B) in perpendicular direction and moves in circular path of radius 'r'. Then 'r' is equal to (m and e be the mass and charge of electron respectively) ____________.


A light of frequency 'v' is incident on the metal surface whose threshold frequency is 'v0'. If v = v0, then [c = speed of light in medium] ____________.


Is it always necessary to use red light to get a photoelectric effect?


The radiation corresponding to the 3 → 2 transition of a hydrogen atom falls on a gold surface to generate photoelectrons. These electrons are passed through a magnetic field of 5 × 10-4 T. Assume that the radius of the largest circular path followed by these electrons is 7 mm, and the work function of the metal is ______.

(Mass of electron = 9.1 × 10-31 kg)


The radiation emitted, when an electron jumps from n = 3 to n = 2 orbit is a hydrogen atom, falls on a metal to produce photoelectron. The electrons from the metal surface with maximum kinetic energy are made to move perpendicular to a magnetic field of `1/320`T in a radius of 10-3m. Find the 320 work function of metal:


When ultraviolet light of wavelength 100 nm is incident upon a sample of silver metal, a potential difference of 7.7 volt is required to stop the photoelectrons from reaching the collector plate. The potential required to stop photo electrons when light of wavelength 200 nm is incident upon silver is ______.


The maximum kinetic energy of the photoelectrons ejected will be ______ eV when the light of wavelength 350 nm is incident on a cesium surface. The work function of cesium = 1.9 eV.


A point isotropic light source of power P = 12 watts is located on the axis of a circular mirror of radius R = 3 cm. If the distance of the source from the centre of the mirror is a = 39 cm and the reflection coefficient of the mirror is α = 0.70 then the force exerted by the light ray on the mirror is ______ × 10-10 N.


The following graphs show the variation of stopping potential corresponding to the frequency of incident radiation (ν) for a given metal. The correct variation is shown in graph [ν0 = threshold frequency].

(A)

(B)

(C)

(D)


Explain the failure of wave theory of light to account for the observations from experiments on photoelectric effect.


Define photoelectric work function of a metal.


Give Einstein's explanation of the photoelectric effect.


Draw a neat labelled diagram of photo-current as a function of accelerating potential for fixed incident intensity but different incident frequencies for the same emitter material.


In a photoelectric experiment, the stopping potential is 1.5V. What is the maximum kinetic energy of a photoelectron?


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×