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Question
If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?
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Solution
Let Zeba’s age = x
According to the question,
(x – 5)2 = 11 + 5x
x2 + 25 – 10x = 11 + 5x
x2 – 15x + 14 = 0
x2 – 14x – x + 14 = 0
x(x – 14) – 1(x – 14) = 0
x = 1 or x = 14
We have to neglect 1 as 5 years younger than 1 cannot happen.
Therefore, Zeba’s present age = 14 years.
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