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If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now? - Mathematics

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प्रश्न

If Zeba were younger by 5 years than what she really is, then the square of her age (in years) would have been 11 more than five times her actual age. What is her age now?

योग
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उत्तर

Let Zeba’s age = x

According to the question,

(x – 5)2 = 11 + 5x

x2 + 25 – 10x = 11 + 5x

x2 – 15x + 14 = 0

x2 – 14x – x + 14 = 0

x(x – 14) – 1(x – 14) = 0

x = 1 or x = 14

We have to neglect 1 as 5 years younger than 1 cannot happen.

Therefore, Zeba’s present age = 14 years.

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अध्याय 4: Quadatric Euation - Exercise 4.4 [पृष्ठ ४२]

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एनसीईआरटी एक्झांप्लर Mathematics [English] Class 10
अध्याय 4 Quadatric Euation
Exercise 4.4 | Q 5 | पृष्ठ ४२

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