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If y = ax+b, prove that y(d2ydx2)+(dydx)2 = 0.

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Question

If y = `sqrt(ax + b)`, prove that `y((d^2y)/dx^2) + (dy/dx)^2` = 0.

Sum
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Solution

Given, y = `sqrt(ax + b)`

Then, `dy/dx = a/(2sqrt(ax + b)`

`\implies dy/dx = a/(2y)`

`\implies y dy/dx = a/2`

Again, differentiating with respect to x, we get

`\implies y(d^2y)/(dx^2) + dy/dx xx dy/dx` = 0

`\implies y(d^2y)/(dx^2) + (dy/dx)^2` = 0

Hence Proved.

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