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Question
If (x+a) is a factor of the polynomial `2x^2 + 2ax + 5x + 10`, find the value of a.
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Solution
Given: (x + a) is a factor of `2x^2 + 2ax + 5x + 10`
So, we have
x + a = 0
⇒ x = –a
Now, it will satisfy the above polynomial.
Therefore, we will get
`2 (–a)^2 + 2a(–a) + 5(–a) + 10 = 0`
`⇒ 2a^2 –2a^2 – 5a + 10 = 0`
`⇒ – 5a = – 10`
`⇒ a = 2`
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