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Question
One zero of the polynomial `3x^3+16x^2 +15x-18 is 2/3` . Find the other zeros of the polynomial.
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Solution
Given: `x =2/3` is one of the zero of` 3x^3 + 16x^2 + 15x – 18`
Now, we have
`x=2/3`
`⇒ x-2/3=0`
Now, we divide `3x^3 + 16x^2 + 15x – 18 by x –2/3` to find the quotient 
So, the quotient is `3x^2+18x+27`
Now,
`3x^2 + 18x + 27 = 0`
⇒ `3x^2 + 9x + 9x + 27 = 0`
⇒ `3x(x + 3) + 9(x + 3) = 0`
⇒ (x + 3) (3x + 9) = 0
⇒ (x + 3) = 0 or (3x + 9) = 0
⇒ x = –3 or x = –3
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