Question

If the distance between the points (4, k) and (1, 0) is 5, then what can be the possible value of k?

Answer 1

Consider the points A(4, k) and B(1, 0).

It is given that the distance AB is 5 units.

By distance formula, distance AB is as follows:

`AB = sqrt((4-1)^2 + (k - 0)^2)`

`=> 5 = sqrt(9 + (k)^2)`

`=> 25 = 9 + k^2`

`=> 16 = k^2`

`=> +- 4 = k`

Hence, value of k are `+- 4`.