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Question
Find the value(s) of x, if the distance between the points A(0, 0) and B(x, –4) is 5 units.
Sum
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Solution
Given: A(0, 0), B(x, –4), distance AB = 5.
Step-wise calculation:
1. Distance formula:
`AB = sqrt((x - 0)^2 + (-4 - 0)^2)`
= `sqrt(x^2 + 16)`
2. Set equal to 5:
`sqrt(x^2 + 16) = 5`
3. Square both sides:
x2 + 16 = 25
4. Solve:
x2 = 9
⇒ x = ±3
Verify: For x = 3 or –3,
`sqrt(9 + 16) = sqrt(25)`
= 5
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