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Question
If the distance between the points (3, x) and (–2, –6) is 13 units, then find the value of x.
Sum
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Solution
Given: Points (3, x) and (–2, –6), distance = 13.
Step-wise calculation:
1. Use the distance formula:
Distance = `sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2`
2. `sqrt((3 - (-2))^2 + (x - (-6))^2) = 13`
3. `sqrt(5^2 + (x + 6)^2) = 13`
4. Square both sides: 25 + (x + 6)2 = 169
5. (x + 6)2 = 144
6. x + 6 = ±12
⇒ x = 6 or x = –18
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