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If tan A = B56,tanB=111, prove that A + B = π4

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Question

If tan A = `5/6, tan "B" = 1/11`, prove that A + B = `pi/4`

Sum
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Solution

We have, tan A = `5/6` and tan B = `1/11`

∴ tan(A + B) = `(tan"A" + tan"B")/(1 - tan"A".tan"B")`

∴ tan(A + B) = `(5/6 + 1/11)/(1 - (5/6)(1/11))`

∴ tan(A + B) = `(55 + 6)/(66 - 5)`

∴ tan(A + B) = `61/61`

∴ tan(A + B) = 1

∴ tan(A + B) = 1 = `tan  π/4`

∴ A + B = `π/4`

Hence proved.

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Chapter 3: Trigonometry - 2 - Exercise 3.1 [Page 40]

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