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Prove the following: tan A + 2 tan 2A + 4 tan 4A + 8 cot 8A = cot A

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Question

Prove the following:

tan A + 2 tan 2A + 4 tan 4A + 8 cot 8A = cot A

Sum
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Solution

L.H.S. = tan A + 2 tan 2A + 4 tan 4A + 8 cot 8A

= `tan"A" + 2tan2"A" + 4tan4"A" + 8/(tan8"A")`

= `tan"A" + 2tan2"A" + 4tan4"A" + (8(1 - tan^2 4"A"))/(2tan4"A")  ...[because tan2theta = (2tantheta)/(1 - tan^2theta)]`

= `tan"A" + 2tan2"A" + (8tan^2 4"A" + 8 - 8tan^2 4"A")/(2tan4"A")`

= `tan"A" + 2tan2"A" + 4/(tan4"A")`

= `tan"A" + 2tan2"A" + (4(1 - tan^2 2"A"))/(2tan2"A")`

= `tan"A" + (4tan^2 2"A" + 4 - 4tan^2 2"A")/(2tan2"A")`

= `tan"A" + 2/(tan2"A")`

= `tan"A" + (2(1 - tan^2"A"))/(2tan"A")`

= `(2tan^2"A" + 2 - 2tan^2"A")/(2tan"A")`

= `1/tan"A"`

= cot A

= R.H.S.

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Chapter 3: Trigonometry - 2 - Miscellaneous Exercise 3 [Page 58]

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Balbharati Mathematics and Statistics (Arts and Science) Part 1 [English] Standard 11 Maharashtra State Board
Chapter 3 Trigonometry - 2
Miscellaneous Exercise 3 | Q II. (18) | Page 58

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