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If show thatdydxlog5(x4+y4x4-y4)=2,show thatdydx=12x313y3.

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Question

If `log_5((x^4 + y^4)/(x^4 - y^4)) = 2, "show that""dy"/"dx" = (12x^3)/(13y^3)`.

Sum
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Solution

`log_5((x^4 + y^4)/(x^4 - y^4))` = 2

`(x^4 + y^4)/(x^4 - y^4)` = 52

`(x^4 + y^4)/(x^4 - y^4)` = 25

`(x^4 + y^4)/(x^4 - y^4)` = 25

x4 + y4 = 25(x4 – y)

x4 + y4 = 25x4 – 25y4

y4 + 25y= 25x4 − x4 

26y4 = 24x4 

Differentiating both sides w.r.t.x, we get

`26d/dxy^4 = 24"d"/"dx"x^4`

`26. 4y^3 dy/dx = 24. 4x^3 d/dx x`

`26y^3  dy/dx = 24x^3`

`dy/dx = (24x^3)/(26y^3)`

`dy/dx = (12x^3)/(13y^3)`

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Notes

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Chapter 1: Differentiation - Exercise 1.3 [Page 40]

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