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Question
If the polynomials ax3 + 3x2 − 13 and 2x3 − 5x + a, when divided by (x − 2) leave the same remainder, find the value of a.
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Solution
Let us denote the given polynomials as
`f(x) = ax^3 + 3x^2 - 13`
`g(x) = 2x^3 - 5x + a,`
`h(x) = x -2`
Now, we will find the remainders R1and R2 when f(x) and g(x)respectively are divided by h(x).
By the remainder theorem, when f(x) is divided by h(x) the remainder is
`R_1 = f(2)`
` = a(2)^3 + 3(2)^2 - 13`
` = 8a + 12 - 13`
` = 8a - 1`
By the remainder theorem, when g(x) is divided by h (x) the remainder is
`R_2 = g(2)`
` = 2(2)^3 - 5 (2) + a`
` = 16 - 10 + a`
` = a+6`
By the given condition, the two remainders are same. Then we have, R1 = R2
`⇒ 8a - 1 = a+ 6`
`⇒ 8a - a = 6+1`
`⇒ 7a = 7`
`⇒ a =7/ 7`
`⇒ a = 1`
`⇒ a = 1`
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