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Question
Find the integral roots of the polynomial f(x) = x3 + 6x2 + 11x + 6.
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Solution
The given polynomial is
`f (x) = x^3 + 6x^2 + 11x + 6`
Here, f(x) is a polynomial with integer coefficient and the coefficient of highest degree term is 1. So, the integer roots of f(x) are factors of 6. Which are ±1, ±2, ±3, ±6 by observing.
`f(-1) = (-1)^3 + 6xx (-1)^2 + 11(-1) + 6`
` = -1 + 6 - 11 + 6`
` = -12 + 12`
= 0
Also,
`f(-2) = (-2)^3 + 6(-2)^2 + 11(-2) + 6`
` = -8 + 6 xx 4 - 22 + 6`
` = -8 + 42 - 22 + 6`
`= 30 - 30`
` = 0`
And similarly,
f(−3) = 0
Therefore, the integer roots of the polynomial f(x) are −1, −2, − 3.
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