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Question
If `sum"p"_0"q"_0` = 150, `sum"p"_0"q"_1` = 250, `sum"p"_1"q"_1` = 375 and P01(L) = 140. Find P01(M-E)
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Solution
Given, `sum"p"_0"q"_0` = 150, `sum"p"_0"q"_1` = 250, `sum"p"_1"q"_1` = 375 and P01(L) = 140
P01(L) = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100`
140 = `(sum"p"_1"q"_0)/150 xx 100`
`sum"p"_1"q"_0 = (140 xx 150)/100` = 210
P01(M-E) = `(sum"p"_1"q"_0 + sum"p"_1"q"_1)/(sum"p"_0"q"_0 + sum"p"_0"q"_1) xx 100`
= `(210 + 375)/(150 + 250) xx 100`
= `585/400 xx 100`
= 146.25
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