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Question
If f(x) = 2{x} + 5x, where {x} is fractional part function of x, then find f(– 1)
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Solution
f(x) = 2{x} + 5x, where {x} = x – [x]
f(– 1) = 2{– 1} + 5(– 1)
= 2(– 1 – [– 1]) – 5
= 2(– 1 + 1) – 5
= 2(0) – 5
= – 5
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