Advertisements
Advertisements
Question
If the diagonals of a rhombus are 18 cm and 24 cm respectively, then its side is equal to
Options
16 cm
15 cm
20 cm
17 cm
Advertisements
Solution
Let ABCD be rhombus with diagonals AC and BD 18cm and 24cm respectively.

We know that diagonals of the rhombus bisect each other at right angles.
Therefore,
`AO = 1/2 AC `
`AO = 1/2 (18cm) `
AO = 9cm
Similarly,
`BO = 1/2 BD `
`BO = 1/2(24cm)`
BO = 12cm
Also, ΔAOB is a right angled triangle.
By Pythagoras theorem, we get:
`AB^2 = AO^2 + BO^2`
`AB = sqrt(AO^2 + BO^2)`
`AB = sqrt(9^2 + 12^2)`
`AB = sqrt225`
AB = 15cm
Hence the correct choice is (b).
APPEARS IN
RELATED QUESTIONS

Find x + y + z

Find x + y + z + w
Find x in the following figures.

If PQRS is a square, then write the measure of ∠SRP.
If the angles of a quadrilateral are in the ratio 3 : 5 : 9 : 13, then find the measure of the smallest angle.
The diagonals of a rectangle ABCD meet at O, If ∠BOC = 44°, find ∠OAD.
Can all the angles of a quadrilateral be right angles? Give reason for your answer.
The angles of a quadrilateral are in the ratio 1 : 2 : 3 : 4. The smallest angle is ______.
The sum of all ______ of a quadrilateral is 360°.
In a quadrilateral PQRS, ∠P = 50°, ∠Q = 50°, ∠R = 60°. Find ∠S. Is this quadrilateral convex or concave?
