Advertisements
Advertisements
Question
If a + b + c = p and ab + bc + ca = q ; find a2 + b2 + c2.
Advertisements
Solution
We know that
( a + b + c )2 = a2 + b2 + c2 + 2( ab + bc + ca ) .....(1)
Given that, a + b + c = p and ab + bc + ca = q
We need to find a2 + b2 + c2 :
Substitute the values of ( ab + bc + ca ) and ( a + b + c )
in the identity (1), we have
(p)2 = a2 + b2 + c2 + 2q
⇒ p2 = a2 + b2 + c2 + 2q
⇒ a2 + b2 + c2 = p2 - 2q
APPEARS IN
RELATED QUESTIONS
Expand : ( x + 8 ) ( x + 10 )
Expand : `( x - 1/x + 5)^2`
If a2 + b2 + c2 = 35 and ab + bc + ca = 23; find a + b + c.
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x3.
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
If `(x^2 + 1)/x = 3 1/3` and x > 1; find If `x^3 - 1/x^3`
Find the value of 'a': 4x2 + ax + 9 = (2x + 3)2
The sum of two numbers is 7 and the sum of their cubes is 133, find the sum of their square.
