Expand : ( X - 1/X + 5)^2

Expand : `( x - 1/x + 5)^2`

Sum

`( x - 1/x + 5)^2 = (x)^2 + (1/x)^2 + (5)^2 - 2(x)(1/x) - 2(1/x)(5) + 2(5)(x)`

=`x^2 + 1/x^2 + 25 - 2 - 10/x + 10x`

=`x^2 + 1/x^2 + 23 - 10/x + 10x`

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Expansion of Formula

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (C) [Page 62]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (C) | Q 3.5 | Page 62

Expand : ( x - 2y + 2 )²

Expand : ( 5a - 3b + c )²

If a² + b² + c² = 35 and ab + bc + ca = 23; find a + b + c.

In the expansion of (2x² - 8) (x - 4)²; find the value of coefficient of x³.

In the expansion of (2x² - 8) (x - 4)²; find the value of constant term.

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If 2( x² + 1 ) = 5x, find :
(i) `x - 1/x`

(ii) `x^3 - 1/x^3`

If a² + b² = 34 and ab = 12; find : 7(a - b)² - 2(a + b)²

If 3x - `4/x` = 4; and x ≠ 0 find : 27x³ - `64/x^3`

If x = `1/( x - 5 ) "and x ≠ 5. Find" : x^2 - 1/x^2`