In the Expansion of (2x2 - 8) (X - 4)2; Find the Value of Constant Term.

In the expansion of (2x² - 8) (x - 4)²; find the value of constant term.

Sum

( 2x² - 8 )( x - 4 )²
= ( 2x² - 8 )( x² - 8x + 16 )
= 4x⁴ - 16x³ + 32x² - 8x² + 64x -128
= 4x⁴ - 16x³ + 24x² + 64x - 128
Hence,
Constant term = -128

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Expansion of Formula

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Chapter 4: Expansions (Including Substitution) - Exercise 4 (D) [Page 64]

Chapter 4 Expansions (Including Substitution)
Exercise 4 (D) | Q 3.3 | Page 64

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