Advertisements
Advertisements
Question
If a2 + b2 + c2 = 35 and ab + bc + ca = 23; find a + b + c.
Advertisements
Solution
We know that
(a + b + c)2 = a2 + b2 + c2 + 2(ab + bc + ca) ...(1)
Given that, a2 + b2 + c2 = 35 and ab + bc + ca = 23
We need to find a + b + c :
Substitute the values of (a2 + b2 + c2) and (ab + bc + ca)
in the identity (1), we have
(a + b + c)2 = 35 + 2(23)
⇒ (a + b + c)2 = 81
⇒ a + b + c = `+-sqrt81`
⇒ a + b + c = `+-9`
APPEARS IN
RELATED QUESTIONS
Expand : ( 5a - 3b + c )2
If x+ y - z = 4 and x2 + y2 + z2 = 30, then find the value of xy - yz - zx.
If x + 2y + 3z = 0 and x3 + 4y3 + 9z3 = 18xyz ; evaluate :
`[( x + 2y )^2]/(xy) + [(2y + 3z)^2]/(yz) + [(3z + x)^2]/(zx)`
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
If a + `1/a` = m and a ≠ 0; find in terms of 'm'; the value of `a^2 - 1/a^2`.
If 3x - `4/x` = 4; and x ≠ 0 find : 27x3 - `64/x^3`
If `(x^2 + 1)/x = 3 1/3` and x > 1; find If `x^3 - 1/x^3`
Find the value of 'a': 4x2 + ax + 9 = (2x + 3)2
The sum of two numbers is 7 and the sum of their cubes is 133, find the sum of their square.
If x = `1/[ 5 - x ] "and x ≠ 5 find "x^3 + 1/x^3`
