Advertisements
Advertisements
प्रश्न
If a + b + c = p and ab + bc + ca = q ; find a2 + b2 + c2.
Advertisements
उत्तर
We know that
( a + b + c )2 = a2 + b2 + c2 + 2( ab + bc + ca ) .....(1)
Given that, a + b + c = p and ab + bc + ca = q
We need to find a2 + b2 + c2 :
Substitute the values of ( ab + bc + ca ) and ( a + b + c )
in the identity (1), we have
(p)2 = a2 + b2 + c2 + 2q
⇒ p2 = a2 + b2 + c2 + 2q
⇒ a2 + b2 + c2 = p2 - 2q
APPEARS IN
संबंधित प्रश्न
Expand : `( 3a + 2/b )( 2a - 3/b )`
Expand : ( 5x - 3y - 2 )2
If a + `1/a` = m and a ≠ 0; find in terms of 'm'; the value of `a^2 - 1/a^2`.
If x > 0 and `x^2 + 1/[9x^2] = 25/36, "Find" x^3 + 1/[27x^3]`
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
If x2 + `x^(1/2)`= 7 and x ≠ 0; find the value of:
7x3 + 8x − `7/x^3 - 8/x`
If `(x^2 + 1)/x = 3 1/3` and x > 1; Find `x - 1/x`.
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
Find the value of 'a': 9x2 + (7a - 5)x + 25 = (3x + 5)2
If x = `1/[ 5 - x ] "and x ≠ 5 find "x^3 + 1/x^3`
