Advertisements
Advertisements
प्रश्न
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x2
Advertisements
उत्तर
( 2x2 - 8 )( x - 4 )2
= ( 2x2 - 8 )( x2 - 8x + 16 )
= 2x4 - 16x3 + 32x2 - 8x2 + 64x -128
= 2x4 - 16x3 + 24x2 + 64x - 128
Hence,
Coefficient of x2 = 24
APPEARS IN
संबंधित प्रश्न
Expand : ( x + 8 )( x - 10 )
Expand : ( x - 8 )( x - 10 )
Expand: `( 2x - 1/x )( 3x + 2/x )`
Expand : ( 5x - 3y - 2 )2
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x3.
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : Their product
The difference between two positive numbers is 4 and the difference between their cubes is 316.
Find : The sum of their squares
If `(x^2 + 1)/x = 3 1/3` and x > 1; Find `x - 1/x`.
If 3a + 5b + 4c = 0, show that : 27a3 + 125b3 + 64c3 = 180 abc
