Advertisements
Advertisements
प्रश्न
In the expansion of (2x2 - 8) (x - 4)2; find the value of coefficient of x2
Advertisements
उत्तर
( 2x2 - 8 )( x - 4 )2
= ( 2x2 - 8 )( x2 - 8x + 16 )
= 2x4 - 16x3 + 32x2 - 8x2 + 64x -128
= 2x4 - 16x3 + 24x2 + 64x - 128
Hence,
Coefficient of x2 = 24
APPEARS IN
संबंधित प्रश्न
Expand : ( x - 2y + 2 )2
If a + b + c = p and ab + bc + ca = q ; find a2 + b2 + c2.
If a2 + b2 + c2 = 50 and ab + bc + ca = 47, find a + b + c.
If x + 2y + 3z = 0 and x3 + 4y3 + 9z3 = 18xyz ; evaluate :
`[( x + 2y )^2]/(xy) + [(2y + 3z)^2]/(yz) + [(3z + x)^2]/(zx)`
If a + `1/a` = m and a ≠ 0 ; find in terms of 'm'; the value of :
`a - 1/a`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If 2( x2 + 1 ) = 5x, find :
(i) `x - 1/x`
(ii) `x^3 - 1/x^3`
If a2 + b2 = 34 and ab = 12; find : 3(a + b)2 + 5(a - b)2
Find the value of 'a': 4x2 + ax + 9 = (2x - 3)2
Find the value of 'a': 9x2 + (7a - 5)x + 25 = (3x + 5)2
