Advertisements
Advertisements
Question
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
Sum
Advertisements
Solution
3a + 2b − 6c + 4d
= 3 × 3 + 2 × 0 − 6 × 2 + 4 × 1
= 9 + 0 − 12 + 4
= 9 + 0 − (12 − 4)
= 9 − 8
= 1
shaalaa.com
Is there an error in this question or solution?
RELATED QUESTIONS
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
xz + cd = ...................
State true and false:
The value of x + 5 = 6, when x = 1
Evaluate:
(9a – 3a) + 4a
Fill in the blank:
6p − 5x + q = 6p − (...........)
Insert the bracket as indicated:
x2 − y2 + z2 = x2 − (..................)
Find the value of 3ab + 10bc – 2abc when a = 2, b = 5 and c = 8.
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
Simplify:
6 {3x – 8 (5x – 10)}
Evaluate (2 + x) × y when x = 3, y = 4:
Evaluate x² + y when x = 2, y = 3:
