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प्रश्न
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
योग
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उत्तर
3a + 2b − 6c + 4d
= 3 × 3 + 2 × 0 − 6 × 2 + 4 × 1
= 9 + 0 − 12 + 4
= 9 + 0 − (12 − 4)
= 9 − 8
= 1
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