Advertisements
Advertisements
प्रश्न
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
Advertisements
उत्तर
3a + 2b − 6c + 4d
= 3 × 3 + 2 × 0 − 6 × 2 + 4 × 1
= 9 + 0 − 12 + 4
= 9 + 0 − (12 − 4)
= 9 − 8
= 1
APPEARS IN
संबंधित प्रश्न
If x = 2, y = 5 and z = 4, find the value of the following:
yx
Evaluate:
(23 – 15) + 4
Simplify:
− m − n − (− m) − m
Simplify:
x + y − (x + `overline("y"-"x"))`
Simplify:
x − (y − z) + x + (y − z) + y − (z + x)
Insert the bracket as indicated:
m + n − p = − (.............)
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find Q + P
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P + Q + R
If x = a2 – bc, y = b2 – ca, and z = c2 – ab; find the value of ay – bx + cz
