Advertisements
Advertisements
प्रश्न
If a = 3, b = 0, c = 2 and d = 1, find the value of 3a + 2b − 6c + 4d
Advertisements
उत्तर
3a + 2b − 6c + 4d
= 3 × 3 + 2 × 0 − 6 × 2 + 4 × 1
= 9 + 0 − 12 + 4
= 9 + 0 − (12 − 4)
= 9 − 8
= 1
संबंधित प्रश्न
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
z ÷ x = ..................
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
b + z − d = ....................
Fill in the blank, when:
x = 3, y = 6, z = 18, a = 2, b = 8, c = 32 and d = 0.
d − a + x = ................
Find the value of 5x + 3y − 6z, when x = 3, y = 5 and z = 4
Find the value of `("a+b"-"c")/(2"a")`, when a = 5, b = 7 and c = 2
Simplify:
3x + (8x − 5x) − (7x − x)
Simplify:
`5{"a"^2-"a"("a"-overline("a"-2))}`
If x = 3, y = 2 and z = 1; find the value of 2x – 3y + 4z + 5
If P = − 12x2 – 10xy + 5y2, Q = 7x2 + 6xy + 2y2, and R = 5x2 + 2xy + 4y2 ; find P – Q + R
Multiply and then evaluate:
(4x + y) and (x – 2y); when x = 2 and y = 1.
