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Question
If 3x + 2y = 13 and xy = 6, find the value of 9x2 + 4y2.
Sum
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Solution
Given: 3x + 2y = 13 and xy = 6
Step-wise calculation:
1. We want to find the value of 9x2 + 4y2.
2. Notice that (3x + 2y)2 = 9x2 + 12xy + 4y2
3. Substitute 3x + 2y = 13:
132 = 9x2 + 12xy + 4y2
169 = 9x2 + 12xy + 4y2
4. Now, substitute xy = 6:
169 = 9x2 + 12(6) + 4y2
169 = 9x2 + 72 + 4y2
5. Rearrange to isolate 9x2 + 4y2:
9x2 + 4y2 = 169 – 72
9x2 + 4y2 = 97
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