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If 3x + 2y = 13 and xy = 6, find the value of 9x^2 + 4y^2. - Mathematics

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प्रश्न

If 3x + 2y = 13 and xy = 6, find the value of 9x2 + 4y2.

योग
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उत्तर

Given: 3x + 2y = 13 and xy = 6

Step-wise calculation:

1. We want to find the value of 9x2 + 4y2.

2. Notice that (3x + 2y)2 = 9x2 + 12xy + 4y2

3. Substitute 3x + 2y = 13:

132 = 9x2 + 12xy + 4y2

169 = 9x2 + 12xy + 4y2

4. Now, substitute xy = 6: 

169 = 9x2 + 12(6) + 4y2 

169 = 9x2 + 72 + 4y2

5. Rearrange to isolate 9x2 + 4y2:

9x2 + 4y2 = 169 – 72

9x2 + 4y2 = 97

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अध्याय 3: Expansions - Exercise 3B [पृष्ठ ७१]

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नूतन Mathematics [English] Class 9 ICSE
अध्याय 3 Expansions
Exercise 3B | Q 4. | पृष्ठ ७१
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