Advertisements
Advertisements
Question
If `2"x"-1/(2"x")=4`, find : `4"x"^2+1/(4"x"^2)`
Advertisements
Solution
`2"x"-1/"2x"=4`
`⇒(2"x"-1/"2x")^2=(4)^2`
`⇒(2"x")^2+(1/"2x")^2-2xx2"x"xx1/"2x"=16`
`⇒4"x"^2+1/"4x"^2-2=16`
`⇒4"x"^2+1/"4x"^2=16+2`
`⇒4"x"^2+1/"4x"^2=18`
APPEARS IN
RELATED QUESTIONS
If a+b=5 and ab = 6, find a2 + b2
If `"a" - 1/"a"=4`, find : `"a"^2+1/"a"^2`
If `"a"^2+ 1/"a"^2=11`, find : `"a" -1/"a"`
Find : a + b + c, if a2 + b2 + c2 = 83 and ab + bc + ca = 71.
Find : `"a"^3+1/"a"^3`, if `"a" +1/"a"=5`.
If `3"x"+1/(3"x")=3`, find : `27"x"^3+1/(27"x"^3)`
The sum of the squares of two numbers is 13 and their product is 6. Find:
(i) the sum of the two numbers.
(ii) the difference between them.
If a2 + b2 = 41 and ab = 4, find : a – b
If 3x – 4y = 5 and xy = 3, find : 27x3 – 64y3.
The difference between the two numbers is 5 and their products are 14. Find the difference between their cubes.
