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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Identify the type of conic and find centre, foci, vertices, and directrices of the following: (y-2)325+(x+1)216 = 1 - Mathematics

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Question

Identify the type of conic and find centre, foci, vertices, and directrices of the following:

`(y - 2)^3/25 + (x + 1)^2/16` = 1

Sum
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Solution

It is a hyperbola.

The transverse axis is parallel to y axis.

a2 = 25, b2 = 16

a = ± 5, b = 4

c2 = a2 + b2

= 25 + 16

= 41

c = `sqrt(41)`

ae = `sqrt(41)`

5e = `sqrt(41)`

e = `sqrt(41)/5`

Centre (h, k) = (– 1, 2)

Vertices (h, ± a + k) = (– 1, ± 5 + 2)

= (– 1, 5 + 2) and (– 1, – 5 + 2)

= (– 1, 7) and (– 1, – 3)

Foci (h, ± c + k) = `(- 1 +-  sqrt(41) + 2)`

= `(-1, sqrt(41) + 2)` and `(-1, - sqrt(41) + 2)`

Directrix x = `+-  "a"/"e" + "k"`

= `+-  5/(sqrt(41)/5) + 2`

= `+-  25/sqrt(41) + 2`

y = `25/sqrt(41) + 2` and y = `- 25/sqrt(41) + 2`

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Chapter 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [Page 197]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 8. (iv) | Page 197

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