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Tamil Nadu Board of Secondary EducationHSC Science Class 12

Find the equation of the hyperbola in the cases given below: Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4 - Mathematics

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Question

Find the equation of the hyperbola in the cases given below:

Centre (2, 1), one of the foci (8, 1) and corresponding directrix x = 4

Sum
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Solution

Distance CS = ae = 6 .......(1)

Directrix  `"a"/x` = 4  .......(2)

(1) × (2)

⇒ ae × `"a"/"e"` = 24

a2 = 24

∴ c = ae = 6

b2 = c2 – a2

= 36 – 24 = 12

The transverse axis is parallel to x-axis

∴ `(x - "h")^2/"a"^2 - (y - "k")^2/"b"^2` = 1(h, k) = (2, 1)

`(x - 2)^2/24 - (y - 1)^2/12` = 1

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Chapter 5: Two Dimensional Analytical Geometry-II - Exercise 5.2 [Page 196]

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Samacheer Kalvi Mathematics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 5 Two Dimensional Analytical Geometry-II
Exercise 5.2 | Q 3. (ii) | Page 196

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