Advertisements
Advertisements
Question
The distance between directrix and focus of a parabola y2 = 4ax is:
Options
a
2a
4a
3a
Advertisements
Solution
2a
APPEARS IN
RELATED QUESTIONS
The parabola y2 = kx passes through the point (4, -2). Find its latus rectum and focus.
Find the axis, vertex, focus, equation of directrix and the length of latus rectum of the parabola (y - 2)2 = 4(x - 1)
The focus of the parabola x2 = 16y is:
The equation of directrix of the parabola y2 = -x is:
Find the equation of the parabola in the cases given below:
Focus (4, 0) and directrix x = – 4
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
`x^2/3 + y^2/10` = 1
Prove that the length of the latus rectum of the hyperbola `x^2/"a"^2 - y^2/"b"^2` = 1 is `(2"b"^2)/"a"`
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
18x2 + 12y2 – 144x + 48y + 120 = 0
Identify the type of conic and find centre, foci, vertices, and directrices of the following:
9x2 – y2 – 36x – 6y + 18 = 0
If the eccentricity e > 1, the conic section is:
