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Question
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with iron (II) sulphide.
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Solution
Gas Evolved: When dilute hydrochloric acid reacts with iron (II) sulphide, the gas evolved is hydrogen sulphide.
Reaction:
\[\ce{FeS + 2HCl -> FeCl2 + H2S ^}\]
Chemical Test for Hydrogen Sulphide: To test for H2S gas, you can use lead acetate paper:
- Moisten a strip of lead acetate paper.
- Expose it to the gas that evolved.
Observation: If H2S is present, the lead acetate paper will turn black due to the formation of lead sulphide (PbS).
\[\ce{Pb(C2H3O2)2 + H2S -> PbS + 2CH3COOH}\]
RELATED QUESTIONS
Write balanced chemical equations to show : The oxidizing action of conc. Sulphuric acid on carbon
A, B, C, and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.
A = Typical acid property
B = Non volatile acid
C = Oxidizing agent
D = Dehydrating agent
Choose the property (A, B, C or D) depending on which is relevant to each of the following
1) Preparation of Hydrogen chloride gas
2) Preparation of Copper sulphate from copper oxide.
3) An action of conc. Sulphuric acid on Sulphur.
The acid which is used in the preparation of a volatile acid
Name the products formed when hot and concentrated sulphuric acid reacts with Sulphur.
Name the Following:
The property used to prepare HCl and HNO3 from H2SO4.
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
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State your observation for the following case :
Dry red rose petals are placed in the jar of sulphur dioxide.
Give two balanced reactions of the type to show the following property of sulphuric acid:
Dehydrating nature
The salt is formed when concentrated sulphuric acid reacts with KNO3 above 200°C.
Convert the following reaction into a balanced chemical equation:
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