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प्रश्न
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with iron (II) sulphide.
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उत्तर
Gas Evolved: When dilute hydrochloric acid reacts with iron (II) sulphide, the gas evolved is hydrogen sulphide.
Reaction:
\[\ce{FeS + 2HCl -> FeCl2 + H2S ^}\]
Chemical Test for Hydrogen Sulphide: To test for H2S gas, you can use lead acetate paper:
- Moisten a strip of lead acetate paper.
- Expose it to the gas that evolved.
Observation: If H2S is present, the lead acetate paper will turn black due to the formation of lead sulphide (PbS).
\[\ce{Pb(C2H3O2)2 + H2S -> PbS + 2CH3COOH}\]
संबंधित प्रश्न
Distinguish between the given pairs of compounds using the test given within brackets:
Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)
Give one equation to show the following properties of sulphuric acid:
As a non-volatile acid
Give reason for the following:
When concentrated sulphuric acid is added to sugar/glucose, a black mass is left behind.
What would you see, when a crystal of CuSO4.5H2O is placed in concentrated sulphuric acid? Give reason to explain your observation.
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Zinc hydroxide
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Sodium Sulphate from sodium carbonate.
Give one equation to show the following property of sulphuric acid:
Acidic nature
Write a balanced equation for the following conversion:
Lead sulphate from lead nitrate and sulphuric acid.
Convert the following reaction into a balanced chemical equation:
Sodium hydroxide to sodium sulphate using sulphuric acid.
Differentiate between the following pair based on the criteria given in the bracket:
Cane sugar and hydrated copper sulphate [using concentrated H2SO4]
