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प्रश्न
Identify the gas evolved and give the chemical test in the following case:
Dilute hydrochloric acid reacts with iron (II) sulphide.
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उत्तर
Gas Evolved: When dilute hydrochloric acid reacts with iron (II) sulphide, the gas evolved is hydrogen sulphide.
Reaction:
\[\ce{FeS + 2HCl -> FeCl2 + H2S ^}\]
Chemical Test for Hydrogen Sulphide: To test for H2S gas, you can use lead acetate paper:
- Moisten a strip of lead acetate paper.
- Expose it to the gas that evolved.
Observation: If H2S is present, the lead acetate paper will turn black due to the formation of lead sulphide (PbS).
\[\ce{Pb(C2H3O2)2 + H2S -> PbS + 2CH3COOH}\]
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संबंधित प्रश्न
Identify the acid in the following case:
The acid on mixing with lead nitrate solution produces a white precipitate, which is insoluble even on heating.
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Potassium hydrogen carbonate.
Give one equation to show the following properties of sulphuric acid:
As a non-volatile acid
Name the following:
The precipitate obtained by treating aqueous barium chloride with dilute sulphuric acid.
What would you observe in the following case?
Concentrated sulphuric acid is added to equal volumes of cold water.
Sulphuric acid can be used to prepare a number of gases in the laboratory. Write balanced equation for the reaction from which the folllowing gas are obtained, using dilute sulphuric acid as one of the reactant : Carbon dioxide
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Copper carbonate
Write balanced equation for the reaction of dilute sulphuric acid with the following:
Zinc hydroxide
State one appropriate observation of the following:
Concentrated sulphuric acid is added dropwise to a crystal of hydrated copper sulphate.
Complete the table given below:
| Name of the process | Reactants | Acid product formed |
| (a) ______ | Nitrogen dioxide + water + oxygen | (b) ______ |
| (c) ______ | Oleum + water | Sulphuric acid |
