Advertisements
Advertisements
प्रश्न
State one relevant observation for given reactions:
Action of concentrated Sulphuric acid on hydrated copper sulfate
Advertisements
उत्तर
Concentrated sulphuric acid removes water of crystallization from blue-colored hydrated copper sulfate to form white anhydrous copper sulfate.
APPEARS IN
संबंधित प्रश्न
A, B, C, and D summarize the properties of sulphuric acid depending on whether it is dilute or concentrated.
A = Typical acid property
B = Non volatile acid
C = Oxidizing agent
D = Dehydrating agent
Choose the property (A, B, C or D) depending on which is relevant to each of the following
1) Preparation of Hydrogen chloride gas
2) Preparation of Copper sulphate from copper oxide.
3) An action of conc. Sulphuric acid on Sulphur.
Distinguish between the given pairs of compounds using the test given within brackets:
Dilute sulphuric acid and dilute hydrochloric acid (using barium chloride solution)
Which property of sulphuric acid is shown by the reaction of the concentrated sulphuric acid with carbon?
Give a chemical test to distinguish between dilute sulphuric acid and conc. sulphuric acid.
What would you observe in the following case?
Dilute sulphuric acid is added to ferrous sulphate solution.
Give reason for the following:
When solution of sulphur dioxide is exposed to air, it gets converted to sulphuric acid.
How are the following conversion brought about? Give equation and condition:
Dilute sulphuric acid to hydrogen.
Write the equation for the laboratory preparation of the following salts, using sulphuric acid.
Lead sulphate from lead nitrate.
Write the equation of the following reaction:
Sulphur is heated with concentrated sulphuric acid.
A, B and C are the chemical properties of sulphuric acid:
A. Oxidizing agent
B. Dehydrating agent
C. Non-volatile acid
Match the following equations 1 to 3 to the above chemical properties of sulphuric acid.
1. \[\ce{KNO3 + H2SO4 -> KHSO4 + HNO3}\]
2. \[\ce{C12H22O11 -> 12C + 11H2O}\]
3. \[\ce{S + 2H2SO4 -> 2H2O + 3SO2}\]
