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Question
Identify ‘A’ and ‘B’ in the following reaction :
\[\ce{CH3 - CH = CH2 ->[HBr]'A' ->[alc.KOH]'B'}\]
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Solution
\[\begin{array}{cc}
\ce{CH3 - CH = CH2->[HBr] CH3 -CH-CH3->[alc.KOH]CH3-CH=CH3}\\
\phantom{....}\text{Propene}\phantom{......................}|\phantom{....................}\text{Propene(B)}\phantom{..}\\
\text{Br}\\
\text{Isopropyl bromide (A)}
\end{array}\]
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