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Question
How will you prepare cinnamic acid from benzaldehyde?
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Solution
Conversion of benzaldehyde into cinnamic acid:
\[\begin{array}{cc}
\phantom{....}\ce{COOH}\phantom{...............}\ce{COOH}\phantom{......}\\
\phantom{....}/\phantom{.....................}/\phantom{.............}\\
\ce{\underset{(Benzaldehyde)}{C6H5CH = O} + H2C ->[Pyridine][-H2O] C6H5CH = C ->[\Delta][-CO2] \underset{(Cinnamic acid)}{C6H5CH = CH} - COOH}\\
\phantom{....}\backslash\phantom{.....................}\backslash\phantom{.............}\\
\phantom{}\ce{\underset{(Malonic acid)}{COOH}}\phantom{.............}\ce{COOH}\phantom{....}
\end{array}\]
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\[\begin{array}{cc} \phantom{...}\ce{R}\phantom{....}\ce{OR''}\phantom{}\\ \phantom{}\backslash\phantom{..}/\\ \ce{C}\\ \phantom{}/\phantom{..}\backslash\\ \phantom{...}\ce{R'}\phantom{...}\ce{OR''}\phantom{} \end{array}\]
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