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प्रश्न
How will you prepare cinnamic acid from benzaldehyde?
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उत्तर
Conversion of benzaldehyde into cinnamic acid:
\[\begin{array}{cc}
\phantom{....}\ce{COOH}\phantom{...............}\ce{COOH}\phantom{......}\\
\phantom{....}/\phantom{.....................}/\phantom{.............}\\
\ce{\underset{(Benzaldehyde)}{C6H5CH = O} + H2C ->[Pyridine][-H2O] C6H5CH = C ->[\Delta][-CO2] \underset{(Cinnamic acid)}{C6H5CH = CH} - COOH}\\
\phantom{....}\backslash\phantom{.....................}\backslash\phantom{.............}\\
\phantom{}\ce{\underset{(Malonic acid)}{COOH}}\phantom{.............}\ce{COOH}\phantom{....}
\end{array}\]
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संबंधित प्रश्न
Write a note on Stephen reaction.
The product formed after reaction between benzaldehyde and methyl magnesium iodide followed by acid hydrolysis is ____________.
Which of the following is Schiff's reagent?
The compound which does NOT undergo haloform reaction is ____________.
Identify A, B, C and D.
\[\ce{ethanoic acid ->[SOCl2] A ->[Pd/BaSO4] B ->[NaOH] C ->[][\Delta] D}\]
Which one of the following reactions will not result in the formation of a carbon-carbon bond?
Which of the following compounds does not undergo a haloform reaction?
Write the structure of the products obtained from the following ketones by action of hydrazine in presence of strong base KOH.
Write the structure of the major product of the aldol condensation of benzaldehyde with acetone.
Write the structure of the major product of the aldol condensation of benzaldehyde with acetone.
